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Re: double slit experiment

Ok, JSMR state on their website (instructions) that the chip contains quantum material. However, all existing matter is ultimately quantum, so that a statement as general and vague like this is not helping a lot. Why aren't they more specific?

I never said the chip did not contain q-dots, what I've said is that q-dots are not capable of doing what is claimed that they do. To begin with, the laser light can not get out of the CDP to activate the dot. If it did, one would have to position the dot exactly where the laser beam exits the CDP (which, however, is not requested by the instructions). A dot that can't be activated remains inactive.

Even if the dot was activated, how does the IR-emission get back into the CDP? How do q-dot photons change transparency of the CD? Why do I have to put the CD to treated into the drawer, knowing that the laser also works with the drawer empty? It should be possible to "treat" a CD by putting it close to te chip anywhere outside the player. Q-dots do not contain "charges" which can be used up. If there's energy input above the band gap energy, a q-dot is activated.

Problem is that the more you tell about the product the more questions arise which cannot be answered. Even the yeasayers (like Wellfed) do not believe the explanation given on JSMR's site.

Btw,. I've asked two physicist collegues, one of which works in the field of quantum lasers : photons (sunlight, laser or q-dot) follow the rule of wave-particle dualism. Always. Period. Q-dots do not contain charges. Period. Elements like Nb, Cu, Ni, Al, Zn do not point unambiguously towards q-dot, q-wire, q-well.


Klaus

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