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Tweakers' Asylum Tweaks for systems, rooms and Do It Yourself (DIY) help. FAQ. |
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Tweakers' Asylum Tweaks for systems, rooms and Do It Yourself (DIY) help. FAQ. |
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In Reply to: Procrustes' Bed posted by Al Sekela on April 24, 2010 at 15:32:56:
Here's my question...If you parallel multiple RC filters (whether or not you connect a resistor on either side of each cap) the paralleled capacitors "add" but the resistors would "divide" and = (R1 x R2) / (R1 + R2)...right? So if we parallel an RC = (.10uf + 10R) with an RC = (.01uf + 10R) the equivalent RC filter would be RC(eq) = .11uf + 5R. Or is there some more complex calculation needed?Thanks...
Edits: 04/25/10
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Follow Ups
- I'm easily confused.... - rwiley 21:51:56 04/25/10 (7)
- Yes, that's correct, but - Maxamillion 05:36:13 04/26/10 (6)
- I've had good results with... - rwiley 08:00:30 04/26/10 (1)
- RE: I've had good results with... - Maxamillion 13:31:47 04/26/10 (0)
- Without the theory, in practice - bartc 06:15:09 04/26/10 (3)
- Thanks, Bart. Have you tried... - Maxamillion 07:35:05 04/26/10 (2)
- Yes, Max, I tried that too - bartc 07:41:29 04/26/10 (1)
- I will try multiple combos - Maxamillion 08:30:32 04/26/10 (0)
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