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This Post Has Been Edited by the Author
In Reply to: RE: Procrustes' Bed posted by Al Sekela on April 24, 2010 at 15:32:56
Here's my question...If you parallel multiple RC filters (whether or not you connect a resistor on either side of each cap) the paralleled capacitors "add" but the resistors would "divide" and
= (R1 x R2) / (R1 + R2)...right? So if we parallel an RC = (.10uf + 10R) with an RC = (.01uf + 10R) the equivalent RC filter would be RC(eq) = .11uf + 5R. Or is there some more complex calculation needed?
Thanks...
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