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Tweakers' Asylum Tweaks for systems, rooms and Do It Yourself (DIY) help. FAQ. |
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In Reply to: Still can't see doubling posted by Ed Sommer on July 17, 2000 at 10:30:34:
What Mr. Risch is describing I cannot claim to have measured, but makes perfect sense from a scientific point of view."Voltage" is a measure of potential differance--that is the differance between the electric potentials of two different points. If you define the potential of any given point as the differance in it's potential and that of ground (zero), then you can obtain the potential differance by simple subtraction.
Consider your house current. Since it's A/C, it changes constantly. For most homes in the US, the wall current is taken from a transformer outside, in which the center tap of a 240 volt secondary is grounded. This is the "neutral" wire. One of the other wires is the "hot". So, looking at what we call the "top" of the AC wave, the neutral wire is at 0 volts, since it's grounded, and the "hot" wire will be at 120 volts. subtracting, we get +120 volts. Now, at the "bottom" of the AC wave, the neutral wire will still be at zero, but the other wire will be at a lower potential, giving -120. This +/- switching, of course, is perfectly normal AC.
Now, take the situation Mr. Risch is describing. Assume a spike of +50 volts comes down a normally 100 volt circuit through the common mode choke. We know from physics that this additional spike will induce the opposite voltage in the other wire in the choke. So, our incident wire has a potential of 150 volts--that's 100 plus the surge of 50. The other wire has a potential of -50. That's zero plus the -50 volt induced voltage. Now measure the potential between the two...150- -50 = 200....exactly doubling the original 50 volt surge.
Allan
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Follow Ups
- Re: Still can't see doubling - Allan Moyse 22:25:49 07/18/00 (1)
- Re: Still can't see doubling - madalo 16:34:30 07/21/00 (0)
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