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RE: hey core-- i think you did your math wrong!

Posted by corerosin (A) on July 28, 2007 at 09:23:28

In Reply to: hey core-- i think you did your math wrong! posted by stuck.wilson on July 28, 2007 at 03:54:53:

Once again, 1 / 2 Pi R C = F. However, you must add the prototype from the Butterworth filter tables. As this is a single element, high pass filter, you add the prototype value, 2, in the denominator of the equation. So, the equation is: 1 / 2 Pi R C 2 = F. Squishing the numbers, 1 / 2 x 3.14 x 8 x 1 to the minus 6th x 2 = 9,947 hz. Not 20K. Instead, a 10K, 6db, high pass, Butterworth filter right out of the book.

Of course, I could be wrong...............................but I'm not.

Where Butterworth filters get really nasty is when you start building bandpass filters and half the prototype numbers are going in the denominator and the other half are going in the numerator. For a long time I had bandpass filters that came to a perfect point in the pass band until I figured that one out.

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