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Headphone Heights Welcome to Headphone Heights, the place for all your ear bud discussion |
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In Reply to: RE: Loud doesn't mean quality. . . posted by Dawnrazor on October 10, 2019 at 13:22:23:
Good question! I'd need to see a schematic of the headphone amplifier to find out what's going on with the impedance selector.
On the other hand, if the 5-volts output is dropped across the internal impedance and the headphone impedance, it would reduce the maximum power values I calculated in my previous post. If that were the case, then the maximum power delivered to any headphone would be 25% of the values previously calculated when the selector switch is set to match the headphone impedance. The maximum power delivered to any given headphone would be as follows:
[5 / (selector impedance + headphone impedance)]2 x headphone impedance = power
For example, suppose you had headphones with 20-ohms impedance and the selector switch is set to 20-ohms. The power would be as follows:
[5 / (20 + 20)]2 x 20 = 0.3125-watts
If you had an 8-ohm headphone, the maximum power that could be delivered to that headphone would be:
[5 / (20 + 8)]2 x 8 = 0.2551-watts
The maximum power delivered to any headphone would occur when the impedance selector switch is set to the same value as the headphone impedance.
Best regards,
John Elison
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Follow Ups
- RE: Loud doesn't mean quality. . . - John Elison 15:21:08 10/15/19 (4)
- RE: Loud doesn't mean quality. . . - Chef J 13:45:22 04/12/20 (2)
- RE: Loud doesn't mean quality. . . - Dawnrazor 21:09:55 04/14/20 (1)
- RE: Loud doesn't mean quality. . . - Chef J 11:42:24 04/18/20 (0)
- RE: Loud doesn't mean quality. . . - Dawnrazor 20:04:10 10/15/19 (0)
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