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Now c’mon Christine . . .

You clearly stated:-

3600*(6.912+4.608+0.448+1.536+0.256)/8=6.192Gb

therefore your 6.192"Gigabyte" figure is based directly on the aggregate data-rates contained in the parentheses. Moreover, it follows that one such Gigabyte unit (as used here) therefore equates to (1000,000,000 * 8) bits.

But then immediately below you stated: "Total disc capacity of DVD 5 = 4.4Gb" — clearly where the Gigabyte here is the "IT-speak" one, i.e. based on (1024*1024*1024 * 8) bits. Moreover, to most folks, the word "total" implies "everything".

Now with respect, I simply don’t believe that you meant us all to assume that we should then add 300Mb onto that figure for "authoring overheads", taking it to 4.7Gb! ;-)


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