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RE: The full quote is rather less negative

?

Same membrane size, same segments. I've just replaced this:

+UUUU-

with this

+UU- +UU-

and then paralleled the two halves. So if each "U" is 1 ohm, the first is 4 ohms. The two halves are 2 ohms each. Parallel the two halves and you get 1/2 + 1/2 = 1/Rt, so the total load becomes 1 ohm. Same diaphragm area, same foil, just connected differently.

Now you can get back up to a total of 4 ohms by reducing the thickness of the foil traces, and therefore its conductivity and mass, to 1/4 of the original value.


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