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I understand 3 pin XLR balanced connectors ( pin assignments and conceptual design ). My question is: how does a 4 pin connector supply a balanced signal to a headphone with only R+, R- and L+, L-
Follow Ups:
It doesn't use a ground.
You mix up two things here.
Balanced Signal Transport via great Distances (3Pin XLR).
And Balanced Signal generation in the Source.
When you want to drive Your Headphones in the (2nd) balanced Mode, you first need a source, that is able to produce a balanced Output.
(See Bridged Mode)
So, in essence, you need a Source, that could normally drive two Pairs of Headphones, as it sports two independent stereo amps. Now you bridge each of the two amps, so that the left channel of amplifier one produces the positive half of the Wave, the right channel of amplifier one produces the negative half - for just one side of the headphones. The two channels of the second amplifier do the same for the other side of the headphones. This resulting in the quadruple amount of Power, the amp could otherwise produce, with the extra bargain of winning 4dB more s/n ratio.
And, yes, you only need the 4 pins.
Edits: 09/26/19
See--this is what happens when you're in your 70's. Boy do I feel dumb. I was looking at it as a balanced interconnect, which it is not. It's like a speaker wire ( +, - left and +, - right.
Thanks.......
Pin count is:
Pin 1 L-.Pin 2 L+. Pin 3 R-. Pin 4 R+. The shield is not connected so you use 4 pins.
for the signal for the drivers to be operated in balanced mode.
iBasso DX220, DX120. Focal Utopia and Stellia. iBasso SR1. Mr. Speakers, Ether II, Voce stats. Manley, Absolute HPamp. LTA MZ3, Z10e electrostatic amp. Various other headphones, amps, cables etc.
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