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Tweakers' Asylum Tweaks for systems, rooms and Do It Yourself (DIY) help. FAQ. |
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Tweakers' Asylum Tweaks for systems, rooms and Do It Yourself (DIY) help. FAQ. |
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In Reply to: Re: For John R: Question about driver momentum? posted by Jon Risch on May 17, 2000 at 16:55:19:
I keep switching between my electronics classes and my dynamics class -- I think this is where I'm getting confused.I think I understand what you are saying. Let me spell it out and see if I got it right:
The driver reactance seen by the input signal is linear because it is an appropriately damped system. If the system were underdamped then the reproduction of the second wave might be superimposed over the ringing left over from the first wave and distortion would occur.
In a properly damped system overshoot and ringing are kept to a minimum so the system behaves as a linear transducer, the exception being the fact that the voice coil BL is nonlinear to some extent with respect to excursion.
Damping is a factor not only of the compliance of the driver and box but also includes reactance and parasitic resistance from the spider and surround as well as the reactance of the air in the room, the driver mass, and the voice coil magnetic flux density. This is where we get Qms and Qes.
I'm trying to pick all of this up from the AES loudspeaker books and equivalent circuit derivations. I wonder if I can re-take my EE classes gratis since I still owe on my first pass.
Shawn
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Follow Ups
- Re: For John R: Question about driver momentum? - Shawn Harvey 09:26:56 05/18/00 (1)
- Re: For John R: Question about driver momentum? - Jon Risch 17:06:10 05/18/00 (0)
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